Directions (46-50): Study the table carefully and answer the given questions.
Year
|
State P
|
State Q
|
Number of appeared candidates
|
Percentage of appeared candidates who qualified
|
Number of appeared candidates
|
Percentage of appeared candidates who qualified
|
2006
|
450
|
60%
|
–
|
30%
|
2007
|
600
|
43%
|
–
|
45%
|
2008
|
–
|
60%
|
280
|
60%
|
2009
|
480
|
70%
|
550
|
50%
|
2010
|
380
|
–
|
400
|
–
|
Note:Few values are missing in the table (indicated by '–'). A candidate is expected to calculate the missing value, if it is required to answer the given question on the basis of the given information.
If the ratio of the number of qualified candidates from State P in 2009 to that in 2010 is 14 : 9, what is the number of qualified candidates from State P in 2010?
216
252
234
207
198
Solution
The ratio of qualified candidates from State P in 2009 to that in 2010 is 14 : 9.
Now, in 2009 the number of qualified candidates
$=\dfrac{480\times 70}{100} = 336$
Let the number of qualified candidates from State P in 2009 be $14x$ and in 2010 be $9x$.
Then, $14x = 336$
$\therefore \dfrac{336}{4} = 24$
In 2010 the number of qualified candidates $= 9\times 24 = 216$