यदि $tan^2\theta = 1 – e^2 $ है, तो $sec \theta + tan^3\theta cosec \theta$ बराबर होगा
${{\left( 2+{{e}^{2}} \right)}^{\frac{3}{2}}}$
${{\left( 2-{{e}^{2}} \right)}^{\frac{1}{2}}}$
${{\left( 2+{{e}^{2}} \right)}^{\frac{1}{2}}}$
${{\left( 2-{{e}^{2}} \right)}^{\frac{3}{2}}}$