The average price of 80 computers in an electronics shop is Rs. 30,000. If the highest and lowest price computers are sold out then the average price of the remaining 78 computers is Rs. 29,500. The cost of the highest priced computer is Rs. 80,000. Then the cost of lowest price computer is:
Rs. 19,000
Rs. 20,000
Rs. 29,000
Can't be determined
None of these
Solution
The sum of prices of the costliest and cheapest computer
= $(80 \times 30000) - (78 \times 29500)$ = 99,000
Therefore, the price of the cheapest computer is = 99,000 - 80,000 = Rs. 19,000