If $4^{\log_3\sqrt{3}} +9^{\log_2(2)^2} = 10^{\log_x83},(x \in R)$ then what is the value of $x$.
Solution
$4^{\log_3\sqrt{3}} +9^{\log_2(2)^2} = 10^{\log_x83}$
$2^{\log_{3}^3} + g^{2 wg_{2}^2} = 10^{\log_x 83}$
$2 + g^2 = 10^{\log_x 83}$
$83 = 10^{\log x 83}$
$x=10$