Directions for Questions 31 - 35: In each question two equations numbered I and II are given. You have to solve both the equations and mark answer:
I. ${{x}^{2}}=49$
II. ${{y}^{2}}+15y+56=0$
$x \lt y$
$x \gt y$
$x\le y$
$x\ge y$
$x=y$ or relationship between $x$ and $y$ cannot be established
Solution
I. ${{x}^{2}}=49$
$x=~\sqrt{49}$
$x=~\pm 7$
II. ${{y}^{2}}+15y+56=0$
${{y}^{2}}+~\left( 8+7 \right)y+56=0$
${{y}^{2}}+8y+7y+56=0$
$y\left( y+8 \right)+7(y+8)=0$
$\left( y+7 \right)(y+8)=0$
$y=-7,~-8$
After comparison both equations, the conclusion is
$x\ge y$