Directions for Questions 31 - 35: In each question two equations numbered I and II are given. You have to solve both the equations and mark answer:
I. ${{x}^{2}}+~5x+4=0$
II. $y=~\sqrt{16}$
$x \lt y$
$x \gt y$
$x\le y$
$x\ge y$
$x=y$ or relationship between $x$ and $y$ cannot be established
Solution
I. ${{x}^{2}}+~5x+4=0$
${{x}^{2}}+~(4+1)x+4=0$
${{x}^{2}}+~4x+x+4=0$
$x\left( x+4 \right)+~1\left( x+4 \right)=~0$
$\left( x+4 \right)\left( x+1 \right)=~0$
$x=~-4,~-1$
II. $y=~\sqrt{16}$
$y=~4$
After comparison of both equations, the conclusion is
$x \lt y$