सरल करें : $\dfrac{a}{{{M}^{a+b+c}}}~\times \dfrac{b}{{{M}^{a+b+c}}}~\times \dfrac{c}{{{M}^{a+b+c}}}$
1
M
0
${{M}^{abc}}$
Solution
$M^{\frac{a}{a+b+c}}~\times M^{\frac{b}{a+b+c}}~\times M^{\frac{c}{a+b+c}}$
$= M^{\frac{a}{a+b+c}+ \frac{b}{a+b+c}+ \frac{c}{a+b+c}}$
$= M^{\frac{a+b+c}{a+b+c}}=M^1=M$