The vertices of a$\triangle ABC$ are A(-1, 6), B(-3, - 9) and C (5, - 8). The equation of median BE is
Solution
Point 'E' is the mid point of 'AC'.
E $= \left( \dfrac{5 - 1}{2}, \dfrac{6 - 8}{2}\right)$
E $= (2, -1)$
Now, the equation of BE is-
$(y + 9) = \dfrac{8}{5} (x + 3)$
$\Rightarrow 5y - 8x + 21 = 0$
BE $= 8x - 5y - 21 = 0$