There is a conical vessel with an internal radius of 12 cm. and a height of 42 cm. This vessel is full of water. This water is then poured into a cylindrical vessel of an internal radius of 21 cm. What will be the height to which the water will rise in this cylinder?
Solution
Volume of water $=\dfrac{1}{3} \pi \times 12\times 12\times 42 = 6336$ cc
Let the height to which the water rises be $h$ cm
Volume of water in the cylindrical vessel $= \pi \times 21\times 21\times h = 1386 h$
Since two volumes are equal, $1386 h = 6338$
Hence, $h = 4.6$ cm